Base | Representation |
---|---|
bin | 10010101010001000… |
… | …001011100001100101 |
3 | 1220201012202202212212 |
4 | 102222020023201211 |
5 | 312012214442021 |
6 | 13111545053205 |
7 | 1306315245122 |
oct | 225210134145 |
9 | 56635682785 |
10 | 20034140261 |
11 | 8550828113 |
12 | 3a71487205 |
13 | 1b7379c285 |
14 | d80a51749 |
15 | 7c3c6185b |
hex | 4aa20b865 |
20034140261 has 2 divisors, whose sum is σ = 20034140262. Its totient is φ = 20034140260.
The previous prime is 20034140249. The next prime is 20034140279. The reversal of 20034140261 is 16204143002.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 16634550625 + 3399589636 = 128975^2 + 58306^2 .
It is a cyclic number.
It is not a de Polignac number, because 20034140261 - 214 = 20034123877 is a prime.
It is a super-2 number, since 2×200341402612 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034140281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017070130 + 10017070131.
It is an arithmetic number, because the mean of its divisors is an integer number (10017070131).
Almost surely, 220034140261 is an apocalyptic number.
It is an amenable number.
20034140261 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034140261 is an equidigital number, since it uses as much as digits as its factorization.
20034140261 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 20034140261 its reverse (16204143002), we get a palindrome (36238283263).
The spelling of 20034140261 in words is "twenty billion, thirty-four million, one hundred forty thousand, two hundred sixty-one".
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