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200341452431 is a prime number
BaseRepresentation
bin1011101010010101000…
…1111111011010001111
3201011010010210021011202
42322211101333122033
511240244402434211
6232011404340115
720321435151101
oct2724521773217
9634103707152
10200341452431
1177a6758849a
12329b1b4463b
1315b79ca1933
1499a75a5571
15532842053b
hex2ea547f68f

200341452431 has 2 divisors, whose sum is σ = 200341452432. Its totient is φ = 200341452430.

The previous prime is 200341452427. The next prime is 200341452473. The reversal of 200341452431 is 134254143002.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 200341452431 - 22 = 200341452427 is a prime.

It is a super-2 number, since 2×2003414524312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 200341452394 and 200341452403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200341452401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100170726215 + 100170726216.

It is an arithmetic number, because the mean of its divisors is an integer number (100170726216).

Almost surely, 2200341452431 is an apocalyptic number.

200341452431 is a deficient number, since it is larger than the sum of its proper divisors (1).

200341452431 is an equidigital number, since it uses as much as digits as its factorization.

200341452431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 29.

Adding to 200341452431 its reverse (134254143002), we get a palindrome (334595595433).

The spelling of 200341452431 in words is "two hundred billion, three hundred forty-one million, four hundred fifty-two thousand, four hundred thirty-one".