Base | Representation |
---|---|
bin | 1001000111000100111000… |
… | …11101011100000101010101 |
3 | 2121221021011110121211112111 |
4 | 10203202130131130011111 |
5 | 10111220323210301240 |
6 | 110335353205551021 |
7 | 4135301633616142 |
oct | 443423435340525 |
9 | 77837143554474 |
10 | 20034352431445 |
11 | 6424580720250 |
12 | 22b6960115471 |
13 | b243012c5351 |
14 | 4d394c75b3c9 |
15 | 24b215b4e1ea |
hex | 12389c75c155 |
20034352431445 has 32 divisors (see below), whose sum is σ = 27621763344000. Its totient is φ = 13796264263680.
The previous prime is 20034352431419. The next prime is 20034352431479. The reversal of 20034352431445 is 54413425343002.
It is not a de Polignac number, because 20034352431445 - 211 = 20034352429397 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20034352431398 and 20034352431407.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3100540 + ... + 7048549.
It is an arithmetic number, because the mean of its divisors is an integer number (863180104500).
Almost surely, 220034352431445 is an apocalyptic number.
It is an amenable number.
20034352431445 is a deficient number, since it is larger than the sum of its proper divisors (7587410912555).
20034352431445 is a wasteful number, since it uses less digits than its factorization.
20034352431445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10151013.
The product of its (nonzero) digits is 691200, while the sum is 40.
Adding to 20034352431445 its reverse (54413425343002), we get a palindrome (74447777774447).
The spelling of 20034352431445 in words is "twenty trillion, thirty-four billion, three hundred fifty-two million, four hundred thirty-one thousand, four hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •