Base | Representation |
---|---|
bin | 1011101010010101110… |
… | …0111110100000110101 |
3 | 201011010100012120200002 |
4 | 2322211130332200311 |
5 | 11240301122113331 |
6 | 232011550201045 |
7 | 20321501504246 |
oct | 2724534764065 |
9 | 634110176602 |
10 | 200344332341 |
11 | 77a6917518a |
12 | 329b2ab3185 |
13 | 15b7a76c71a |
14 | 99a7b14ccd |
15 | 53287dd9cb |
hex | 2ea573e835 |
200344332341 has 4 divisors (see below), whose sum is σ = 201142517184. Its totient is φ = 199546147500.
The previous prime is 200344332329. The next prime is 200344332347. The reversal of 200344332341 is 143233443002.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200344332341 is a prime.
It is a super-2 number, since 2×2003443323412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200344332347) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 399092045 + ... + 399092546.
It is an arithmetic number, because the mean of its divisors is an integer number (50285629296).
Almost surely, 2200344332341 is an apocalyptic number.
It is an amenable number.
200344332341 is a deficient number, since it is larger than the sum of its proper divisors (798184843).
200344332341 is an equidigital number, since it uses as much as digits as its factorization.
200344332341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 798184842.
The product of its (nonzero) digits is 20736, while the sum is 29.
Adding to 200344332341 its reverse (143233443002), we get a palindrome (343577775343).
The spelling of 200344332341 in words is "two hundred billion, three hundred forty-four million, three hundred thirty-two thousand, three hundred forty-one".
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