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200345145133 = 728620735019
BaseRepresentation
bin1011101010010110000…
…0000100111100101101
3201011010101201212121111
42322211200010330231
511240301324121013
6232012015432021
720321511431020
oct2724540047455
9634111655544
10200345145133
1177a6967a911
12329b3225611
1315b7a995673
1499a7c871b7
1553288ee73d
hex2ea5804f2d

200345145133 has 4 divisors (see below), whose sum is σ = 228965880160. Its totient is φ = 171724410108.

The previous prime is 200345145131. The next prime is 200345145151. The reversal of 200345145133 is 331541543002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 200345145133 - 21 = 200345145131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200345145095 and 200345145104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200345145131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14310367503 + ... + 14310367516.

It is an arithmetic number, because the mean of its divisors is an integer number (57241470040).

Almost surely, 2200345145133 is an apocalyptic number.

It is an amenable number.

200345145133 is a deficient number, since it is larger than the sum of its proper divisors (28620735027).

200345145133 is an equidigital number, since it uses as much as digits as its factorization.

200345145133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28620735026.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 200345145133 its reverse (331541543002), we get a palindrome (531886688135).

The spelling of 200345145133 in words is "two hundred billion, three hundred forty-five million, one hundred forty-five thousand, one hundred thirty-three".

Divisors: 1 7 28620735019 200345145133