Base | Representation |
---|---|
bin | 1001000111000101010000… |
… | …11000110010111110101111 |
3 | 2121221021200102011110101022 |
4 | 10203202220120302332233 |
5 | 10111221230422303403 |
6 | 110335425115004355 |
7 | 4135306613541212 |
oct | 443425030627657 |
9 | 77837612143338 |
10 | 20034552541103 |
11 | 6424673678631 |
12 | 22b69b71396bb |
13 | b243338ba529 |
14 | 4d396b16b779 |
15 | 24b2284cad38 |
hex | 1238a8632faf |
20034552541103 has 2 divisors, whose sum is σ = 20034552541104. Its totient is φ = 20034552541102.
The previous prime is 20034552541061. The next prime is 20034552541127. The reversal of 20034552541103 is 30114525543002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20034552541103 - 218 = 20034552278959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20034552541183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10017276270551 + 10017276270552.
It is an arithmetic number, because the mean of its divisors is an integer number (10017276270552).
Almost surely, 220034552541103 is an apocalyptic number.
20034552541103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20034552541103 is an equidigital number, since it uses as much as digits as its factorization.
20034552541103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72000, while the sum is 35.
The spelling of 20034552541103 in words is "twenty trillion, thirty-four billion, five hundred fifty-two million, five hundred forty-one thousand, one hundred three".
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