2003544113 has 2 divisors, whose sum is σ = 2003544114. Its totient is φ = 2003544112.

The previous prime is 2003544097. The next prime is 2003544119. The reversal of 2003544113 is 3114453002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1926946609 + 76597504 = 43897^2 + 8752^2 .

It is a cyclic number.

It is not a de Polignac number, because 2003544113 - 2⁴ = 2003544097 is a prime.

It is not a weakly prime, because it can be changed into another prime (2003544119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001772056 + 1001772057.

It is an arithmetic number, because the mean of its divisors is an integer number (1001772057).

Almost surely, 2^2003544113 is an apocalyptic number.

It is an amenable number.

2003544113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2003544113 is an equidigital number, since it uses as much as digits as its factorization.

2003544113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 2003544113 is about 44760.9663993082. The cubic root of 2003544113 is about 1260.6648278242.

Adding to 2003544113 its reverse (3114453002), we get a palindrome (5117997115).

The spelling of 2003544113 in words is "two billion, three million, five hundred forty-four thousand, one hundred thirteen".