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200412013 is a prime number
BaseRepresentation
bin10111111001000…
…00101101101101
3111222002222121011
423330200231231
5402301141023
631515305221
74652321404
oct1374405555
9458088534
10200412013
11a314456a
125714b211
133269c9b9
141c88c63b
15128db50d
hexbf20b6d

200412013 has 2 divisors, whose sum is σ = 200412014. Its totient is φ = 200412012.

The previous prime is 200411999. The next prime is 200412029. The reversal of 200412013 is 310214002.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121947849 + 78464164 = 11043^2 + 8858^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-200412013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 200411984 and 200412002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (200412073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100206006 + 100206007.

It is an arithmetic number, because the mean of its divisors is an integer number (100206007).

Almost surely, 2200412013 is an apocalyptic number.

It is an amenable number.

200412013 is a deficient number, since it is larger than the sum of its proper divisors (1).

200412013 is an equidigital number, since it uses as much as digits as its factorization.

200412013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 200412013 is about 14156.6949885911. The cubic root of 200412013 is about 585.2048499724.

Adding to 200412013 its reverse (310214002), we get a palindrome (510626015).

The spelling of 200412013 in words is "two hundred million, four hundred twelve thousand, thirteen".