Search a number
-
+
2004200311 is a prime number
BaseRepresentation
bin111011101110101…
…1010101101110111
312011200020220222011
41313131122231313
513101033402221
6530512545051
7100444264411
oct16735325567
95150226864
102004200311
119393563a3
1247b252187
1325c2b8159
1415026d9b1
15bae421e1
hex7775ab77

2004200311 has 2 divisors, whose sum is σ = 2004200312. Its totient is φ = 2004200310.

The previous prime is 2004200269. The next prime is 2004200333. The reversal of 2004200311 is 1130024002.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2004200311 - 211 = 2004198263 is a prime.

It is a super-2 number, since 2×20042003112 = 8033637773224993442, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2004200291 and 2004200300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2004206311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002100155 + 1002100156.

It is an arithmetic number, because the mean of its divisors is an integer number (1002100156).

Almost surely, 22004200311 is an apocalyptic number.

2004200311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2004200311 is an equidigital number, since it uses as much as digits as its factorization.

2004200311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 2004200311 is about 44768.2958241656. The cubic root of 2004200311 is about 1260.8024432024.

Adding to 2004200311 its reverse (1130024002), we get a palindrome (3134224313).

The spelling of 2004200311 in words is "two billion, four million, two hundred thousand, three hundred eleven".