Base | Representation |
---|---|
bin | 1011101010101101101… |
… | …0110111100111011101 |
3 | 201011101022120201211000 |
4 | 2322223122313213131 |
5 | 11241002234134401 |
6 | 232025524020513 |
7 | 20324125440330 |
oct | 2725332674735 |
9 | 634338521730 |
10 | 200444443101 |
11 | 7800a731951 |
12 | 32a20531739 |
13 | 15b95421766 |
14 | 99b7134617 |
15 | 53324b6186 |
hex | 2eab6b79dd |
200444443101 has 64 divisors (see below), whose sum is σ = 354326999040. Its totient is φ = 109499480640.
The previous prime is 200444443091. The next prime is 200444443103. The reversal of 200444443101 is 101344444002.
200444443101 is a `hidden beast` number, since 200 + 4 + 4 + 4 + 443 + 10 + 1 = 666.
It is not a de Polignac number, because 200444443101 - 26 = 200444443037 is a prime.
It is a super-3 number, since 3×2004444431013 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (200444443103) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 8564946 + ... + 8588316.
It is an arithmetic number, because the mean of its divisors is an integer number (5536359360).
Almost surely, 2200444443101 is an apocalyptic number.
200444443101 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
200444443101 is a deficient number, since it is larger than the sum of its proper divisors (153882555939).
200444443101 is a wasteful number, since it uses less digits than its factorization.
200444443101 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25383 (or 25377 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 27.
Adding to 200444443101 its reverse (101344444002), we get a palindrome (301788887103).
Subtracting from 200444443101 its reverse (101344444002), we obtain a palindrome (99099999099).
It can be divided in two parts, 200444 and 443101, that added together give a triangular number (643545 = T1134).
The spelling of 200444443101 in words is "two hundred billion, four hundred forty-four million, four hundred forty-three thousand, one hundred one".
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