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20048128316893 is a prime number
BaseRepresentation
bin1001000111011110100011…
…00100010001010111011101
32121222120201112101022202001
410203233101210101113131
510111432031322120033
6110345552155002301
74136300210663365
oct443572144212735
977876645338661
1020048128316893
11642a3aa865946
1222b9565739391
13b256b8355a61
144d44981759a5
1524b770262e7d
hex123bd19115dd

20048128316893 has 2 divisors, whose sum is σ = 20048128316894. Its totient is φ = 20048128316892.

The previous prime is 20048128316831. The next prime is 20048128316911. The reversal of 20048128316893 is 39861382184002.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15078916052964 + 4969212263929 = 3883158^2 + 2229173^2 .

It is a cyclic number.

It is not a de Polignac number, because 20048128316893 - 213 = 20048128308701 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20048128386893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10024064158446 + 10024064158447.

It is an arithmetic number, because the mean of its divisors is an integer number (10024064158447).

Almost surely, 220048128316893 is an apocalyptic number.

It is an amenable number.

20048128316893 is a deficient number, since it is larger than the sum of its proper divisors (1).

20048128316893 is an equidigital number, since it uses as much as digits as its factorization.

20048128316893 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3981312, while the sum is 55.

The spelling of 20048128316893 in words is "twenty trillion, forty-eight billion, one hundred twenty-eight million, three hundred sixteen thousand, eight hundred ninety-three".