Base | Representation |
---|---|
bin | 11101001011011011010… |
… | …001000011100110100111 |
3 | 21002200121012022200210002 |
4 | 131023123101003212213 |
5 | 230323003130111242 |
6 | 4133051240251515 |
7 | 264603035015453 |
oct | 35133321034647 |
9 | 7080535280702 |
10 | 2005133441447 |
11 | 703410610384 |
12 | 284737170b9b |
13 | 117110c44ca6 |
14 | 6d098569663 |
15 | 372589e2432 |
hex | 1d2db4439a7 |
2005133441447 has 2 divisors, whose sum is σ = 2005133441448. Its totient is φ = 2005133441446.
The previous prime is 2005133441359. The next prime is 2005133441449. The reversal of 2005133441447 is 7441443315002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2005133441447 - 214 = 2005133425063 is a prime.
Together with 2005133441449, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2005133441447.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2005133441449) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002566720723 + 1002566720724.
It is an arithmetic number, because the mean of its divisors is an integer number (1002566720724).
Almost surely, 22005133441447 is an apocalyptic number.
2005133441447 is a deficient number, since it is larger than the sum of its proper divisors (1).
2005133441447 is an equidigital number, since it uses as much as digits as its factorization.
2005133441447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 38.
Adding to 2005133441447 its reverse (7441443315002), we get a palindrome (9446576756449).
The spelling of 2005133441447 in words is "two trillion, five billion, one hundred thirty-three million, four hundred forty-one thousand, four hundred forty-seven".
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