Base | Representation |
---|---|
bin | 11101001011101101001… |
… | …100001001011001001111 |
3 | 21002201101011010222121002 |
4 | 131023231030021121033 |
5 | 230324112120104320 |
6 | 4133141141330515 |
7 | 264613345653326 |
oct | 35135514113117 |
9 | 7081334128532 |
10 | 2005434144335 |
11 | 703555324966 |
12 | 2847bba06a3b |
13 | 11715b32a9ab |
14 | 6d0c64830bd |
15 | 372750de675 |
hex | 1d2ed30964f |
2005434144335 has 16 divisors (see below), whose sum is σ = 2418207390144. Its totient is φ = 1596564110592.
The previous prime is 2005434144299. The next prime is 2005434144353. The reversal of 2005434144335 is 5334414345002.
It is a cyclic number.
It is not a de Polignac number, because 2005434144335 - 212 = 2005434140239 is a prime.
It is a super-3 number, since 3×20054341443353 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1594469 + ... + 2559921.
It is an arithmetic number, because the mean of its divisors is an integer number (151137961884).
Almost surely, 22005434144335 is an apocalyptic number.
2005434144335 is a deficient number, since it is larger than the sum of its proper divisors (412773245809).
2005434144335 is a wasteful number, since it uses less digits than its factorization.
2005434144335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 967474.
The product of its (nonzero) digits is 345600, while the sum is 38.
Adding to 2005434144335 its reverse (5334414345002), we get a palindrome (7339848489337).
The spelling of 2005434144335 in words is "two trillion, five billion, four hundred thirty-four million, one hundred forty-four thousand, three hundred thirty-five".
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