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2005501300739 is a prime number
BaseRepresentation
bin11101001011110001001…
…100010101000000000011
321002201112211111212212022
4131023301030111000003
5230324231313110424
64133151540552055
7264615122534516
oct35136114250003
97081484455768
102005501300739
1170358a223522
1228481a3b262b
1311716c212101
146d0d1364d7d
153727ae5795e
hex1d2f1315003

2005501300739 has 2 divisors, whose sum is σ = 2005501300740. Its totient is φ = 2005501300738.

The previous prime is 2005501300681. The next prime is 2005501300771. The reversal of 2005501300739 is 9370031055002.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2005501300739 - 240 = 905989672963 is a prime.

It is a super-2 number, since 2×20055013007392 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 2005501300699 and 2005501300708.

It is not a weakly prime, because it can be changed into another prime (2005501300139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1002750650369 + 1002750650370.

It is an arithmetic number, because the mean of its divisors is an integer number (1002750650370).

Almost surely, 22005501300739 is an apocalyptic number.

2005501300739 is a deficient number, since it is larger than the sum of its proper divisors (1).

2005501300739 is an equidigital number, since it uses as much as digits as its factorization.

2005501300739 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28350, while the sum is 35.

The spelling of 2005501300739 in words is "two trillion, five billion, five hundred one million, three hundred thousand, seven hundred thirty-nine".