Base | Representation |
---|---|
bin | 11101001011110001010… |
… | …110101101011110100001 |
3 | 21002201120000122011022210 |
4 | 131023301112231132201 |
5 | 230324233012204213 |
6 | 4133152115152333 |
7 | 264615154631502 |
oct | 35136126553641 |
9 | 7081500564283 |
10 | 2005504022433 |
11 | 70359081235a |
12 | 28481b2a56a9 |
13 | 11716c955b92 |
14 | 6d0d1872ba9 |
15 | 3727b2e40c3 |
hex | 1d2f15ad7a1 |
2005504022433 has 32 divisors (see below), whose sum is σ = 2935176072192. Its totient is φ = 1212536678400.
The previous prime is 2005504022413. The next prime is 2005504022437. The reversal of 2005504022433 is 3342204055002.
It is not a de Polignac number, because 2005504022433 - 212 = 2005504018337 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2005504022433.
It is not an unprimeable number, because it can be changed into a prime (2005504022437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2353738 + ... + 3090483.
It is an arithmetic number, because the mean of its divisors is an integer number (91724252256).
Almost surely, 22005504022433 is an apocalyptic number.
It is an amenable number.
2005504022433 is a deficient number, since it is larger than the sum of its proper divisors (929672049759).
2005504022433 is a wasteful number, since it uses less digits than its factorization.
2005504022433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5444505.
The product of its (nonzero) digits is 28800, while the sum is 30.
Adding to 2005504022433 its reverse (3342204055002), we get a palindrome (5347708077435).
The spelling of 2005504022433 in words is "two trillion, five billion, five hundred four million, twenty-two thousand, four hundred thirty-three".
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