Base | Representation |
---|---|
bin | 11101001011110011100… |
… | …100111100111111001111 |
3 | 21002201122121210120211011 |
4 | 131023303210330333033 |
5 | 230324322033413130 |
6 | 4133155530310051 |
7 | 264616116603016 |
oct | 35136344747717 |
9 | 7081577716734 |
10 | 2005541310415 |
11 | 7035aa870375 |
12 | 28482b888327 |
13 | 1171775b0186 |
14 | 6d0d67bba7d |
15 | 3727e70c52a |
hex | 1d2f393cfcf |
2005541310415 has 8 divisors (see below), whose sum is σ = 2413101718368. Its totient is φ = 1600131617760.
The previous prime is 2005541310401. The next prime is 2005541310469. The reversal of 2005541310415 is 5140131455002.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2005541310415 - 29 = 2005541309903 is a prime.
It is a super-2 number, since 2×20055413104152 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 537676771 + ... + 537680500.
It is an arithmetic number, because the mean of its divisors is an integer number (301637714796).
Almost surely, 22005541310415 is an apocalyptic number.
2005541310415 is a deficient number, since it is larger than the sum of its proper divisors (407560407953).
2005541310415 is a wasteful number, since it uses less digits than its factorization.
2005541310415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1075357649.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 2005541310415 its reverse (5140131455002), we get a palindrome (7145672765417).
The spelling of 2005541310415 in words is "two trillion, five billion, five hundred forty-one million, three hundred ten thousand, four hundred fifteen".
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