Base | Representation |
---|---|
bin | 11101001111111101111… |
… | …011101100001000000101 |
3 | 21010011012001110001101112 |
4 | 131033331323230020011 |
5 | 230413000030310432 |
6 | 4135215202134405 |
7 | 265134631121024 |
oct | 35177573541005 |
9 | 7104161401345 |
10 | 2010010010117 |
11 | 70549328261a |
12 | 285678351405 |
13 | 11770a347b95 |
14 | 6d3dc09a8bb |
15 | 37441bb67b2 |
hex | 1d3fdeec205 |
2010010010117 has 2 divisors, whose sum is σ = 2010010010118. Its totient is φ = 2010010010116.
The previous prime is 2010010010101. The next prime is 2010010010119. The reversal of 2010010010117 is 7110100100102.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1463166028996 + 546843981121 = 1209614^2 + 739489^2 .
It is a cyclic number.
It is not a de Polignac number, because 2010010010117 - 24 = 2010010010101 is a prime.
Together with 2010010010119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2010010010119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005005005058 + 1005005005059.
It is an arithmetic number, because the mean of its divisors is an integer number (1005005005059).
Almost surely, 22010010010117 is an apocalyptic number.
It is an amenable number.
2010010010117 is a deficient number, since it is larger than the sum of its proper divisors (1).
2010010010117 is an equidigital number, since it uses as much as digits as its factorization.
2010010010117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 2010010010117 its reverse (7110100100102), we get a palindrome (9120110110219).
The spelling of 2010010010117 in words is "two trillion, ten billion, ten million, ten thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •