Base | Representation |
---|---|
bin | 101101101100111101111001… |
… | …011001000111000011011011 |
3 | 222100200121211200122120022022 |
4 | 231230331321121013003123 |
5 | 202321210012021024011 |
6 | 1551255050243445055 |
7 | 60223634112230633 |
oct | 5554757131070333 |
9 | 870617750576268 |
10 | 201002211111131 |
11 | 59055617067811 |
12 | 1a6636a998678b |
13 | 88205726795b1 |
14 | 378c7b799b6c3 |
15 | 18387de9b98db |
hex | b6cf796470db |
201002211111131 has 2 divisors, whose sum is σ = 201002211111132. Its totient is φ = 201002211111130.
The previous prime is 201002211111017. The next prime is 201002211111133. The reversal of 201002211111131 is 131111112200102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201002211111131 - 222 = 201002206916827 is a prime.
It is a super-2 number, since 2×2010022111111312 (a number of 29 digits) contains 22 as substring.
Together with 201002211111133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (201002211111133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100501105555565 + 100501105555566.
It is an arithmetic number, because the mean of its divisors is an integer number (100501105555566).
Almost surely, 2201002211111131 is an apocalyptic number.
201002211111131 is a deficient number, since it is larger than the sum of its proper divisors (1).
201002211111131 is an equidigital number, since it uses as much as digits as its factorization.
201002211111131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 201002211111131 its reverse (131111112200102), we get a palindrome (332113323311233).
The spelling of 201002211111131 in words is "two hundred one trillion, two billion, two hundred eleven million, one hundred eleven thousand, one hundred thirty-one".
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