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20101112022113 is a prime number
BaseRepresentation
bin1001001001000001001111…
…01001000100010001100001
32122011122111001120102110122
410210200213221010101201
510113314034134201423
6110430153503410025
74143154203024233
oct444404751042141
978148431512418
1020101112022113
11644a919779881
1223078918b3915
13b2a6b02c3215
144d6c82c6a253
1524cd21a2d8c8
hex124827a44461

20101112022113 has 2 divisors, whose sum is σ = 20101112022114. Its totient is φ = 20101112022112.

The previous prime is 20101112022077. The next prime is 20101112022139. The reversal of 20101112022113 is 31122021110102.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19514023531024 + 587088491089 = 4417468^2 + 766217^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-20101112022113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 20101112022091 and 20101112022100.

It is not a weakly prime, because it can be changed into another prime (20101117022113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10050556011056 + 10050556011057.

It is an arithmetic number, because the mean of its divisors is an integer number (10050556011057).

Almost surely, 220101112022113 is an apocalyptic number.

It is an amenable number.

20101112022113 is a deficient number, since it is larger than the sum of its proper divisors (1).

20101112022113 is an equidigital number, since it uses as much as digits as its factorization.

20101112022113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 20101112022113 its reverse (31122021110102), we get a palindrome (51223133132215).

The spelling of 20101112022113 in words is "twenty trillion, one hundred one billion, one hundred twelve million, twenty-two thousand, one hundred thirteen".