Base | Representation |
---|---|
bin | 10010101110001011… |
… | …000101110011100011 |
3 | 1220212221111000120211 |
4 | 102232023011303203 |
5 | 312132103342011 |
6 | 13122411514551 |
7 | 1311101166235 |
oct | 225613056343 |
9 | 56787430524 |
10 | 20102012131 |
11 | 8586075273 |
12 | 3a90158a57 |
13 | 1b84874246 |
14 | d89a7c255 |
15 | 7c9bbbb21 |
hex | 4ae2c5ce3 |
20102012131 has 2 divisors, whose sum is σ = 20102012132. Its totient is φ = 20102012130.
The previous prime is 20102012129. The next prime is 20102012137. The reversal of 20102012131 is 13121020102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20102012131 - 21 = 20102012129 is a prime.
It is a super-2 number, since 2×201020121312 (a number of 21 digits) contains 22 as substring.
Together with 20102012129, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (20102012137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10051006065 + 10051006066.
It is an arithmetic number, because the mean of its divisors is an integer number (10051006066).
Almost surely, 220102012131 is an apocalyptic number.
20102012131 is a deficient number, since it is larger than the sum of its proper divisors (1).
20102012131 is an equidigital number, since it uses as much as digits as its factorization.
20102012131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20102012131 its reverse (13121020102), we get a palindrome (33223032233).
The spelling of 20102012131 in words is "twenty billion, one hundred two million, twelve thousand, one hundred thirty-one".
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