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2010411431317 is a prime number
BaseRepresentation
bin11101010000010101110…
…110111111010110010101
321010012020000210100202101
4131100111312333112111
5230414310311300232
64135323102042101
7265150604132152
oct35202566772625
97105200710671
102010411431317
11705679929283
1228576a879331
13117772566313
146d439511229
153746705b1e7
hex1d415dbf595

2010411431317 has 2 divisors, whose sum is σ = 2010411431318. Its totient is φ = 2010411431316.

The previous prime is 2010411431309. The next prime is 2010411431351. The reversal of 2010411431317 is 7131341140102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1418364284401 + 592047146916 = 1190951^2 + 769446^2 .

It is a cyclic number.

It is not a de Polignac number, because 2010411431317 - 23 = 2010411431309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2010411435317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005205715658 + 1005205715659.

It is an arithmetic number, because the mean of its divisors is an integer number (1005205715659).

Almost surely, 22010411431317 is an apocalyptic number.

It is an amenable number.

2010411431317 is a deficient number, since it is larger than the sum of its proper divisors (1).

2010411431317 is an equidigital number, since it uses as much as digits as its factorization.

2010411431317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 2010411431317 its reverse (7131341140102), we get a palindrome (9141752571419).

The spelling of 2010411431317 in words is "two trillion, ten billion, four hundred eleven million, four hundred thirty-one thousand, three hundred seventeen".