Search a number
-
+
20110000103 = 43467674421
BaseRepresentation
bin10010101110101001…
…100011111111100111
31220220111111212000122
4102232221203333213
5312141130000403
613123255032155
71311226115624
oct225651437747
956814455018
1020110000103
11858a6307a6
123a9296b65b
131b8641005b
14d8ab5b34b
157ca748838
hex4aea63fe7

20110000103 has 4 divisors (see below), whose sum is σ = 20577674568. Its totient is φ = 19642325640.

The previous prime is 20110000063. The next prime is 20110000109. The reversal of 20110000103 is 30100001102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30100001102 = 215050000551.

It is a cyclic number.

It is not a de Polignac number, because 20110000103 - 210 = 20109999079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20110000109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 233837168 + ... + 233837253.

It is an arithmetic number, because the mean of its divisors is an integer number (5144418642).

Almost surely, 220110000103 is an apocalyptic number.

20110000103 is a deficient number, since it is larger than the sum of its proper divisors (467674465).

20110000103 is an equidigital number, since it uses as much as digits as its factorization.

20110000103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 467674464.

The product of its (nonzero) digits is 6, while the sum is 8.

Adding to 20110000103 its reverse (30100001102), we get a palindrome (50210001205).

Subtracting 20110000103 from its reverse (30100001102), we obtain a palindrome (9990000999).

The spelling of 20110000103 in words is "twenty billion, one hundred ten million, one hundred three", and thus it is an aban number.

Divisors: 1 43 467674421 20110000103