Base | Representation |
---|---|
bin | 10010101110101001… |
… | …100011111111110101 |
3 | 1220220111111212001011 |
4 | 102232221203333311 |
5 | 312141130000432 |
6 | 13123255032221 |
7 | 1311226115644 |
oct | 225651437765 |
9 | 56814455034 |
10 | 20110000117 |
11 | 858a630809 |
12 | 3a9296b671 |
13 | 1b8641006c |
14 | d8ab5b35b |
15 | 7ca748847 |
hex | 4aea63ff5 |
20110000117 has 2 divisors, whose sum is σ = 20110000118. Its totient is φ = 20110000116.
The previous prime is 20110000109. The next prime is 20110000147. The reversal of 20110000117 is 71100001102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14524829361 + 5585170756 = 120519^2 + 74734^2 .
It is a cyclic number.
It is not a de Polignac number, because 20110000117 - 23 = 20110000109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 20110000097 and 20110000106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110000147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055000058 + 10055000059.
It is an arithmetic number, because the mean of its divisors is an integer number (10055000059).
Almost surely, 220110000117 is an apocalyptic number.
It is an amenable number.
20110000117 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110000117 is an equidigital number, since it uses as much as digits as its factorization.
20110000117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 13.
Adding to 20110000117 its reverse (71100001102), we get a palindrome (91210001219).
The spelling of 20110000117 in words is "twenty billion, one hundred ten million, one hundred seventeen", and thus it is an aban number.
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