Base | Representation |
---|---|
bin | 1001001001010001110100… |
… | …00100110100000010000110 |
3 | 2122012111110020222112010011 |
4 | 10210220322010310002012 |
5 | 10113440300333020402 |
6 | 110434224524220434 |
7 | 4143620552662666 |
oct | 444507204640206 |
9 | 78174406875104 |
10 | 20110011220102 |
11 | 6453676080a61 |
12 | 230955609a71a |
13 | b2b49ac0b94b |
14 | 4d7488b221a6 |
15 | 24d192e47ed7 |
hex | 124a3a134086 |
20110011220102 has 4 divisors (see below), whose sum is σ = 30165016830156. Its totient is φ = 10055005610050.
The previous prime is 20110011220043. The next prime is 20110011220139. The reversal of 20110011220102 is 20102211001102.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×201100112201023 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5027502805024 + ... + 5027502805027.
It is an arithmetic number, because the mean of its divisors is an integer number (7541254207539).
Almost surely, 220110011220102 is an apocalyptic number.
20110011220102 is a deficient number, since it is larger than the sum of its proper divisors (10055005610054).
20110011220102 is a wasteful number, since it uses less digits than its factorization.
20110011220102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10055005610053.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 20110011220102 its reverse (20102211001102), we get a palindrome (40212222221204).
The spelling of 20110011220102 in words is "twenty trillion, one hundred ten billion, eleven million, two hundred twenty thousand, one hundred two".
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