Base | Representation |
---|---|
bin | 1001001001010001110101… |
… | …01101111100000111001111 |
3 | 2122012111111000021020212111 |
4 | 10210220322231330013033 |
5 | 10113440311113013403 |
6 | 110434225551244451 |
7 | 4143621043424326 |
oct | 444507255740717 |
9 | 78174430236774 |
10 | 20110022001103 |
11 | 6453681174981 |
12 | 2309559819727 |
13 | b2b4a0214b38 |
14 | 4d748a32b0bd |
15 | 24d193d7756d |
hex | 124a3ab7c1cf |
20110022001103 has 2 divisors, whose sum is σ = 20110022001104. Its totient is φ = 20110022001102.
The previous prime is 20110022001079. The next prime is 20110022001107. The reversal of 20110022001103 is 30110022001102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20110022001103 - 213 = 20110021992911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20110022001107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055011000551 + 10055011000552.
It is an arithmetic number, because the mean of its divisors is an integer number (10055011000552).
Almost surely, 220110022001103 is an apocalyptic number.
20110022001103 is a deficient number, since it is larger than the sum of its proper divisors (1).
20110022001103 is an equidigital number, since it uses as much as digits as its factorization.
20110022001103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 20110022001103 its reverse (30110022001102), we get a palindrome (50220044002205).
Subtracting 20110022001103 from its reverse (30110022001102), we obtain a palindrome (9999999999999).
The spelling of 20110022001103 in words is "twenty trillion, one hundred ten billion, twenty-two million, one thousand, one hundred three".
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