201101540100421 has 4 divisors (see below), whose sum is σ = 201104804638432. Its totient is φ = 201098275562412.

The previous prime is 201101540100413. The next prime is 201101540100437. The reversal of 201101540100421 is 124001045101102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 201101540100421 - 2³ = 201101540100413 is a prime.

It is a super-3 number, since 3×201101540100421³ (a number of 44 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 201101540100392 and 201101540100401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201101540100481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1632176601 + ... + 1632299806.

It is an arithmetic number, because the mean of its divisors is an integer number (50276201159608).

Almost surely, 2^{201101540100421} is an apocalyptic number.

It is an amenable number.

201101540100421 is a deficient number, since it is larger than the sum of its proper divisors (3264538011).

201101540100421 is an equidigital number, since it uses as much as digits as its factorization.

201101540100421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3264538010.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 201101540100421 its reverse (124001045101102), we get a palindrome (325102585201523).

The spelling of 201101540100421 in words is "two hundred one trillion, one hundred one billion, five hundred forty million, one hundred thousand, four hundred twenty-one".