Base | Representation |
---|---|
bin | 11101010000111010001… |
… | …001010011011110101111 |
3 | 21010020210110022122001101 |
4 | 131100322021103132233 |
5 | 230422032133242033 |
6 | 4135503330223531 |
7 | 265201645522315 |
oct | 35207211233657 |
9 | 7106713278041 |
10 | 2011020212143 |
11 | 705961534328 |
12 | 2858ba724ba7 |
13 | 11783b717867 |
14 | 6d4963020b5 |
15 | 374a071097d |
hex | 1d43a2537af |
2011020212143 has 2 divisors, whose sum is σ = 2011020212144. Its totient is φ = 2011020212142.
The previous prime is 2011020212093. The next prime is 2011020212161. The reversal of 2011020212143 is 3412120201102.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2011020212143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2011020212143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011020212543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005510106071 + 1005510106072.
It is an arithmetic number, because the mean of its divisors is an integer number (1005510106072).
Almost surely, 22011020212143 is an apocalyptic number.
2011020212143 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011020212143 is an equidigital number, since it uses as much as digits as its factorization.
2011020212143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 2011020212143 its reverse (3412120201102), we get a palindrome (5423140413245).
The spelling of 2011020212143 in words is "two trillion, eleven billion, twenty million, two hundred twelve thousand, one hundred forty-three".
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