Base | Representation |
---|---|
bin | 1001001001010011110101… |
… | …11110101001001111000011 |
3 | 2122012121021010221110202222 |
4 | 10210221322332221033003 |
5 | 10114000013112401201 |
6 | 110434524543201255 |
7 | 4143656544334151 |
oct | 444517276511703 |
9 | 78177233843688 |
10 | 20111100122051 |
11 | 64540847a6124 |
12 | 23097ba8a622b |
13 | b2b6126a5023 |
14 | 4d754d5b23d1 |
15 | 24d20883a91b |
hex | 124a7afa93c3 |
20111100122051 has 2 divisors, whose sum is σ = 20111100122052. Its totient is φ = 20111100122050.
The previous prime is 20111100121963. The next prime is 20111100122053. The reversal of 20111100122051 is 15022100111102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111100122051 - 238 = 19836222215107 is a prime.
Together with 20111100122053, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (20111100122053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055550061025 + 10055550061026.
It is an arithmetic number, because the mean of its divisors is an integer number (10055550061026).
Almost surely, 220111100122051 is an apocalyptic number.
20111100122051 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111100122051 is an equidigital number, since it uses as much as digits as its factorization.
20111100122051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 20111100122051 its reverse (15022100111102), we get a palindrome (35133200233153).
The spelling of 20111100122051 in words is "twenty trillion, one hundred eleven billion, one hundred million, one hundred twenty-two thousand, fifty-one".
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