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20111102011037 is a prime number
BaseRepresentation
bin1001001001010011110110…
…00101110110011010011101
32122012121021021111102222102
410210221323011312122131
510114000014103323122
6110434525051454445
74143656566362332
oct444517305663235
978177237442872
1020111102011037
116454085876374
1223097bb457425
13b2b612bb6a7b
144d754d944989
1524d208ab0492
hex124a7b17669d

20111102011037 has 2 divisors, whose sum is σ = 20111102011038. Its totient is φ = 20111102011036.

The previous prime is 20111102010977. The next prime is 20111102011097. The reversal of 20111102011037 is 73011020111102.

It is a balanced prime because it is at equal distance from previous prime (20111102010977) and next prime (20111102011097).

It can be written as a sum of positive squares in only one way, i.e., 11911292223076 + 8199809787961 = 3451274^2 + 2863531^2 .

It is a cyclic number.

It is not a de Polignac number, because 20111102011037 - 26 = 20111102010973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (20111102011097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055551005518 + 10055551005519.

It is an arithmetic number, because the mean of its divisors is an integer number (10055551005519).

Almost surely, 220111102011037 is an apocalyptic number.

It is an amenable number.

20111102011037 is a deficient number, since it is larger than the sum of its proper divisors (1).

20111102011037 is an equidigital number, since it uses as much as digits as its factorization.

20111102011037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 20.

Adding to 20111102011037 its reverse (73011020111102), we get a palindrome (93122122122139).

The spelling of 20111102011037 in words is "twenty trillion, one hundred eleven billion, one hundred two million, eleven thousand, thirty-seven".