Base | Representation |
---|---|
bin | 1011101101001100100… |
… | …1111101101001100111 |
3 | 201020002210000102011112 |
4 | 2323103021331221213 |
5 | 11243333420200012 |
6 | 232220020455235 |
7 | 20346502100426 |
oct | 2732311755147 |
9 | 636083012145 |
10 | 201111100007 |
11 | 78321a78074 |
12 | 32b8784a51b |
13 | 15c705882bc |
14 | 9a3b8ad2bd |
15 | 5370c9e122 |
hex | 2ed327da67 |
201111100007 has 2 divisors, whose sum is σ = 201111100008. Its totient is φ = 201111100006.
The previous prime is 201111099997. The next prime is 201111100013. The reversal of 201111100007 is 700001111102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201111100007 - 224 = 201094322791 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 201111099964 and 201111100000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201111100207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100555550003 + 100555550004.
It is an arithmetic number, because the mean of its divisors is an integer number (100555550004).
Almost surely, 2201111100007 is an apocalyptic number.
201111100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
201111100007 is an equidigital number, since it uses as much as digits as its factorization.
201111100007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 201111100007 its reverse (700001111102), we get a palindrome (901112211109).
The spelling of 201111100007 in words is "two hundred one billion, one hundred eleven million, one hundred thousand, seven".
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