Base | Representation |
---|---|
bin | 1001001001010100000011… |
… | …00110011000001001100111 |
3 | 2122012121112212221212121211 |
4 | 10210222001212120021213 |
5 | 10114000230031414002 |
6 | 110434543552052251 |
7 | 4143662363441644 |
oct | 444520146301147 |
9 | 78177485855554 |
10 | 20111211201127 |
11 | 6454131474512 |
12 | 230982bb34087 |
13 | b2b62c6c75a7 |
14 | 4d7560248dcb |
15 | 24d21347cdd7 |
hex | 124a81998267 |
20111211201127 has 2 divisors, whose sum is σ = 20111211201128. Its totient is φ = 20111211201126.
The previous prime is 20111211201071. The next prime is 20111211201131. The reversal of 20111211201127 is 72110211211102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111211201127 - 239 = 19561455387239 is a prime.
It is a super-2 number, since 2×201112112011272 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20111211201098 and 20111211201107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111211201427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055605600563 + 10055605600564.
It is an arithmetic number, because the mean of its divisors is an integer number (10055605600564).
Almost surely, 220111211201127 is an apocalyptic number.
20111211201127 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111211201127 is an equidigital number, since it uses as much as digits as its factorization.
20111211201127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 20111211201127 its reverse (72110211211102), we get a palindrome (92221422412229).
The spelling of 20111211201127 in words is "twenty trillion, one hundred eleven billion, two hundred eleven million, two hundred one thousand, one hundred twenty-seven".
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