Base | Representation |
---|---|
bin | 1001001001010100000011… |
… | …00110011000001000101111 |
3 | 2122012121112212221212112202 |
4 | 10210222001212120020233 |
5 | 10114000230031413241 |
6 | 110434543552052115 |
7 | 4143662363441534 |
oct | 444520146301057 |
9 | 78177485855482 |
10 | 20111211201071 |
11 | 6454131474471 |
12 | 230982bb3403b |
13 | b2b62c6c7563 |
14 | 4d7560248d8b |
15 | 24d21347cd9b |
hex | 124a8199822f |
20111211201071 has 2 divisors, whose sum is σ = 20111211201072. Its totient is φ = 20111211201070.
The previous prime is 20111211201001. The next prime is 20111211201127. The reversal of 20111211201071 is 17010211211102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20111211201071 - 218 = 20111210938927 is a prime.
It is a super-3 number, since 3×201112112010713 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111211201001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055605600535 + 10055605600536.
It is an arithmetic number, because the mean of its divisors is an integer number (10055605600536).
Almost surely, 220111211201071 is an apocalyptic number.
20111211201071 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111211201071 is an equidigital number, since it uses as much as digits as its factorization.
20111211201071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 20111211201071 its reverse (17010211211102), we get a palindrome (37121422412173).
The spelling of 20111211201071 in words is "twenty trillion, one hundred eleven billion, two hundred eleven million, two hundred one thousand, seventy-one".
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