Base | Representation |
---|---|
bin | 1001001001010100000100… |
… | …01111100111100011001111 |
3 | 2122012121120122022010111122 |
4 | 10210222002033213203033 |
5 | 10114000240313341421 |
6 | 110434545015511155 |
7 | 4143662554356566 |
oct | 444520217474317 |
9 | 78177518263448 |
10 | 20111222012111 |
11 | 6454137588a0a |
12 | 23098336884bb |
13 | b2b631a11319 |
14 | 4d7561860bdd |
15 | 24d2143b62ab |
hex | 124a823e78cf |
20111222012111 has 2 divisors, whose sum is σ = 20111222012112. Its totient is φ = 20111222012110.
The previous prime is 20111222012059. The next prime is 20111222012171. The reversal of 20111222012111 is 11121022211102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20111222012111 - 210 = 20111222011087 is a prime.
It is a super-2 number, since 2×201112220121112 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20111222012111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20111222012171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10055611006055 + 10055611006056.
It is an arithmetic number, because the mean of its divisors is an integer number (10055611006056).
Almost surely, 220111222012111 is an apocalyptic number.
20111222012111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20111222012111 is an equidigital number, since it uses as much as digits as its factorization.
20111222012111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 20111222012111 its reverse (11121022211102), we get a palindrome (31232244223213).
The spelling of 20111222012111 in words is "twenty trillion, one hundred eleven billion, two hundred twenty-two million, twelve thousand, one hundred eleven".
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