Base | Representation |
---|---|
bin | 11101010001000000101… |
… | …111111100000011111011 |
3 | 21010021002011210101201022 |
4 | 131101000233330003323 |
5 | 230422244014100011 |
6 | 4135522325013055 |
7 | 265204462320155 |
oct | 35210057740373 |
9 | 7107064711638 |
10 | 2011131003131 |
11 | 705a09026228 |
12 | 28592b85418b |
13 | 117858668c63 |
14 | 6d4a6d01ad5 |
15 | 374aa2e78db |
hex | 1d440bfc0fb |
2011131003131 has 8 divisors (see below), whose sum is σ = 2098601308320. Its totient is φ = 1923663183552.
The previous prime is 2011131003103. The next prime is 2011131003143. The reversal of 2011131003131 is 1313001311102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2011131003131 - 26 = 2011131003067 is a prime.
It is a super-2 number, since 2×20111310031312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2011131002131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1138031 + ... + 2305943.
It is an arithmetic number, because the mean of its divisors is an integer number (262325163540).
Almost surely, 22011131003131 is an apocalyptic number.
2011131003131 is a deficient number, since it is larger than the sum of its proper divisors (87470305189).
2011131003131 is a wasteful number, since it uses less digits than its factorization.
2011131003131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1242805.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 2011131003131 its reverse (1313001311102), we get a palindrome (3324132314233).
The spelling of 2011131003131 in words is "two trillion, eleven billion, one hundred thirty-one million, three thousand, one hundred thirty-one".
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