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2011140113 is a prime number
BaseRepresentation
bin111011111011111…
…1001000000010001
312012011022111120212
41313313321000101
513104322440423
6531321413505
7100560260153
oct16767710021
95164274525
102011140113
11942266374
1248163a295
13260877b48
14151158ad3
15bb863578
hex77df9011

2011140113 has 2 divisors, whose sum is σ = 2011140114. Its totient is φ = 2011140112.

The previous prime is 2011140073. The next prime is 2011140127. The reversal of 2011140113 is 3110411102.

It is an a-pointer prime, because the next prime (2011140127) can be obtained adding 2011140113 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1877228929 + 133911184 = 43327^2 + 11572^2 .

It is a cyclic number.

It is not a de Polignac number, because 2011140113 - 210 = 2011139089 is a prime.

It is not a weakly prime, because it can be changed into another prime (2011146113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005570056 + 1005570057.

It is an arithmetic number, because the mean of its divisors is an integer number (1005570057).

Almost surely, 22011140113 is an apocalyptic number.

It is an amenable number.

2011140113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2011140113 is an equidigital number, since it uses as much as digits as its factorization.

2011140113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

The square root of 2011140113 is about 44845.7368430936. The cubic root of 2011140113 is about 1262.2559971279.

Adding to 2011140113 its reverse (3110411102), we get a palindrome (5121551215).

The spelling of 2011140113 in words is "two billion, eleven million, one hundred forty thousand, one hundred thirteen".