Base | Representation |
---|---|
bin | 11101010001000011000… |
… | …011111111011010101111 |
3 | 21010021011212211012110222 |
4 | 131101003003333122233 |
5 | 230422333433023231 |
6 | 4135530232521555 |
7 | 265205443234016 |
oct | 35210303773257 |
9 | 7107155735428 |
10 | 2011169814191 |
11 | 705a28a2458a |
12 | 2859408502bb |
13 | 117863707595 |
14 | 6d4ac125a7d |
15 | 374ad91227b |
hex | 1d4430ff6af |
2011169814191 has 2 divisors, whose sum is σ = 2011169814192. Its totient is φ = 2011169814190.
The previous prime is 2011169814167. The next prime is 2011169814193. The reversal of 2011169814191 is 1914189611102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2011169814191 - 218 = 2011169552047 is a prime.
It is a super-2 number, since 2×20111698141912 (a number of 25 digits) contains 22 as substring.
Together with 2011169814193, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011169814193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005584907095 + 1005584907096.
It is an arithmetic number, because the mean of its divisors is an integer number (1005584907096).
Almost surely, 22011169814191 is an apocalyptic number.
2011169814191 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011169814191 is an equidigital number, since it uses as much as digits as its factorization.
2011169814191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 44.
The spelling of 2011169814191 in words is "two trillion, eleven billion, one hundred sixty-nine million, eight hundred fourteen thousand, one hundred ninety-one".
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