Base | Representation |
---|---|
bin | 11101010001000100111… |
… | …100001000110110010111 |
3 | 21010021021002002100202020 |
4 | 131101010330020312113 |
5 | 230422420013410403 |
6 | 4135533315544223 |
7 | 265206305032566 |
oct | 35210474106627 |
9 | 7107232070666 |
10 | 2011201310103 |
11 | 705a44786967 |
12 | 28594b2bb073 |
13 | 11786a0b440b |
14 | 6d4b23a3bdd |
15 | 374b1584453 |
hex | 1d444f08d97 |
2011201310103 has 8 divisors (see below), whose sum is σ = 2682890367216. Its totient is φ = 1340156563200.
The previous prime is 2011201310017. The next prime is 2011201310117. The reversal of 2011201310103 is 3010131021102.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2011201310103 - 218 = 2011201047959 is a prime.
It is a super-3 number, since 3×20112013101033 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2011201314103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 161070268 + ... + 161082753.
It is an arithmetic number, because the mean of its divisors is an integer number (335361295902).
Almost surely, 22011201310103 is an apocalyptic number.
2011201310103 is a deficient number, since it is larger than the sum of its proper divisors (671689057113).
2011201310103 is a wasteful number, since it uses less digits than its factorization.
2011201310103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322155105.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 2011201310103 its reverse (3010131021102), we get a palindrome (5021332331205).
The spelling of 2011201310103 in words is "two trillion, eleven billion, two hundred one million, three hundred ten thousand, one hundred three".
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