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20112013214 = 210056006607
BaseRepresentation
bin10010101110110001…
…001111011110011110
31220220122022010111022
4102232301033132132
5312142133410324
613123410124142
71311252202016
oct225661173636
956818263438
1020112013214
118590786227
123a93580652
131b86966447
14d8b122c46
157ca9e505e
hex4aec4f79e

20112013214 has 4 divisors (see below), whose sum is σ = 30168019824. Its totient is φ = 10056006606.

The previous prime is 20112013199. The next prime is 20112013219. The reversal of 20112013214 is 41231021102.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41231021102 = 220615510551.

It is a super-2 number, since 2×201120132142 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 20112013192 and 20112013201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20112013219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5028003302 + ... + 5028003305.

It is an arithmetic number, because the mean of its divisors is an integer number (7542004956).

Almost surely, 220112013214 is an apocalyptic number.

20112013214 is a deficient number, since it is larger than the sum of its proper divisors (10056006610).

20112013214 is a wasteful number, since it uses less digits than its factorization.

20112013214 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10056006609.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20112013214 its reverse (41231021102), we get a palindrome (61343034316).

The spelling of 20112013214 in words is "twenty billion, one hundred twelve million, thirteen thousand, two hundred fourteen".

Divisors: 1 2 10056006607 20112013214