Base | Representation |
---|---|
bin | 101101101110101100100111… |
… | …110110101101001100011111 |
3 | 222101002222201102020210001001 |
4 | 231232230213312231030133 |
5 | 202330132004132101421 |
6 | 1551425431524531131 |
7 | 60235343255055511 |
oct | 5556544766551437 |
9 | 871088642223031 |
10 | 201121102222111 |
11 | 590a0a86a96125 |
12 | 1a68274a250aa7 |
13 | 882b83bbbccc6 |
14 | 379445592dbb1 |
15 | 183b94c430691 |
hex | b6eb27dad31f |
201121102222111 has 2 divisors, whose sum is σ = 201121102222112. Its totient is φ = 201121102222110.
The previous prime is 201121102222099. The next prime is 201121102222121. The reversal of 201121102222111 is 111222201121102.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-201121102222111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (201121102222121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100560551111055 + 100560551111056.
It is an arithmetic number, because the mean of its divisors is an integer number (100560551111056).
Almost surely, 2201121102222111 is an apocalyptic number.
201121102222111 is a deficient number, since it is larger than the sum of its proper divisors (1).
201121102222111 is an equidigital number, since it uses as much as digits as its factorization.
201121102222111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 19.
Adding to 201121102222111 its reverse (111222201121102), we get a palindrome (312343303343213).
The spelling of 201121102222111 in words is "two hundred one trillion, one hundred twenty-one billion, one hundred two million, two hundred twenty-two thousand, one hundred eleven".
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