201121411313440 has 24 divisors (see below), whose sum is σ = 475149334228380. Its totient is φ = 80448564525312.

The previous prime is 201121411313429. The next prime is 201121411313447. The reversal of 201121411313440 is 44313114121102.

201121411313440 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 199711502052624 + 1409909260816 = 14131932^2 + 1187396^2 .

It is a super-2 number, since 2×201121411313440² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 201121411313399 and 201121411313408.

It is not an unprimeable number, because it can be changed into a prime (201121411313447) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 628504410195 + ... + 628504410514.

Almost surely, 2^{201121411313440} is an apocalyptic number.

201121411313440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

201121411313440 is an abundant number, since it is smaller than the sum of its proper divisors (274027922914940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

201121411313440 is a wasteful number, since it uses less digits than its factorization.

201121411313440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1257008820724 (or 1257008820716 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 201121411313440 its reverse (44313114121102), we get a palindrome (245434525434542).

The spelling of 201121411313440 in words is "two hundred one trillion, one hundred twenty-one billion, four hundred eleven million, three hundred thirteen thousand, four hundred forty".