Base | Representation |
---|---|
bin | 1001001001010101111001… |
… | …01010011001100011100111 |
3 | 2122012201002221112022201011 |
4 | 10210222330222121203213 |
5 | 10114004242220024312 |
6 | 110435230150443051 |
7 | 4144026055153423 |
oct | 444527452314347 |
9 | 78181087468634 |
10 | 20112202111207 |
11 | 645459a849968 |
12 | 2309a67963487 |
13 | b2b759aa120b |
14 | 4d7615aabb83 |
15 | 24d270465da7 |
hex | 124abca998e7 |
20112202111207 has 2 divisors, whose sum is σ = 20112202111208. Its totient is φ = 20112202111206.
The previous prime is 20112202111151. The next prime is 20112202111223. The reversal of 20112202111207 is 70211120221102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 20112202111207 - 211 = 20112202109159 is a prime.
It is a super-3 number, since 3×201122021112073 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112202111907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056101055603 + 10056101055604.
It is an arithmetic number, because the mean of its divisors is an integer number (10056101055604).
Almost surely, 220112202111207 is an apocalyptic number.
20112202111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112202111207 is an equidigital number, since it uses as much as digits as its factorization.
20112202111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 20112202111207 its reverse (70211120221102), we get a palindrome (90323322332309).
The spelling of 20112202111207 in words is "twenty trillion, one hundred twelve billion, two hundred two million, one hundred eleven thousand, two hundred seven".
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