Base | Representation |
---|---|
bin | 1001001001010101111011… |
… | …01111011110101011001111 |
3 | 2122012201011012121100110022 |
4 | 10210222331233132223033 |
5 | 10114004311334020421 |
6 | 110435232034532355 |
7 | 4144026365115155 |
oct | 444527557365317 |
9 | 78181135540408 |
10 | 20112220220111 |
11 | 64545a9a983a8 |
12 | 2309a71a370bb |
13 | b2b760771946 |
14 | 4d76182633d5 |
15 | 24d271d417ab |
hex | 124abdbdeacf |
20112220220111 has 2 divisors, whose sum is σ = 20112220220112. Its totient is φ = 20112220220110.
The previous prime is 20112220220089. The next prime is 20112220220153. The reversal of 20112220220111 is 11102202221102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20112220220111 - 210 = 20112220219087 is a prime.
It is a super-2 number, since 2×201122202201112 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 20112220220111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20112220220171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10056110110055 + 10056110110056.
It is an arithmetic number, because the mean of its divisors is an integer number (10056110110056).
Almost surely, 220112220220111 is an apocalyptic number.
20112220220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
20112220220111 is an equidigital number, since it uses as much as digits as its factorization.
20112220220111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 20112220220111 its reverse (11102202221102), we get a palindrome (31214422441213).
The spelling of 20112220220111 in words is "twenty trillion, one hundred twelve billion, two hundred twenty million, two hundred twenty thousand, one hundred eleven".
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