Base | Representation |
---|---|
bin | 10010101110110101… |
… | …000000011001001011 |
3 | 1220220201011021010100 |
4 | 102232311000121023 |
5 | 312142412000021 |
6 | 13123443220443 |
7 | 1311263451666 |
oct | 225665003113 |
9 | 56821137110 |
10 | 20113000011 |
11 | 859129a665 |
12 | 3a93977723 |
13 | 1b86c20650 |
14 | d8b2dc6dd |
15 | 7cab3c626 |
hex | 4aed4064b |
20113000011 has 12 divisors (see below), whose sum is σ = 31286889088. Its totient is φ = 12377230704.
The previous prime is 20113000001. The next prime is 20113000013. The reversal of 20113000011 is 11000031102.
It is not a de Polignac number, because 20113000011 - 25 = 20112999979 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 20112999957 and 20113000002.
It is not an unprimeable number, because it can be changed into a prime (20113000013) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 85952875 + ... + 85953108.
Almost surely, 220113000011 is an apocalyptic number.
20113000011 is a deficient number, since it is larger than the sum of its proper divisors (11173889077).
20113000011 is a wasteful number, since it uses less digits than its factorization.
20113000011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 171906002 (or 171905999 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 20113000011 its reverse (11000031102), we get a palindrome (31113031113).
The spelling of 20113000011 in words is "twenty billion, one hundred thirteen million, eleven", and thus it is an aban number.
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