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201131002013 is a prime number
BaseRepresentation
bin1011101101010001010…
…1111000100010011101
3201020011011110112120212
42323110111320202131
511243404014031023
6232222011222205
720350133210654
oct2732425704235
9636134415525
10201131002013
1178332230807
1232b92447965
1315c74735c36
149a403b019b
1553728d0e78
hex2ed457889d

201131002013 has 2 divisors, whose sum is σ = 201131002014. Its totient is φ = 201131002012.

The previous prime is 201131001977. The next prime is 201131002027. The reversal of 201131002013 is 310200131102.

It is an a-pointer prime, because the next prime (201131002027) can be obtained adding 201131002013 to its sum of digits (14).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 172421766169 + 28709235844 = 415237^2 + 169438^2 .

It is a cyclic number.

It is not a de Polignac number, because 201131002013 - 210 = 201131000989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201131002063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100565501006 + 100565501007.

It is an arithmetic number, because the mean of its divisors is an integer number (100565501007).

Almost surely, 2201131002013 is an apocalyptic number.

It is an amenable number.

201131002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

201131002013 is an equidigital number, since it uses as much as digits as its factorization.

201131002013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 201131002013 its reverse (310200131102), we get a palindrome (511331133115).

The spelling of 201131002013 in words is "two hundred one billion, one hundred thirty-one million, two thousand, thirteen".