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2011313400000 = 2635519176431
BaseRepresentation
bin11101010001001011100…
…111101110100011000000
321010021112220000010011220
4131101023213232203000
5230423132212300000
64135552402235040
7265212135550362
oct35211347564300
97107486003156
102011313400000
11705aa1a85743
12285980955a80
1311788739bab8
146d4c3220d32
15374bb3261a0
hex1d44b9ee8c0

2011313400000 has 336 divisors, whose sum is σ = 7001696862720. Its totient is φ = 508118400000.

The previous prime is 2011313399987. The next prime is 2011313400011. The reversal of 2011313400000 is 43131102.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11311785 + ... + 11488215.

It is an arithmetic number, because the mean of its divisors is an integer number (20838383520).

Almost surely, 22011313400000 is an apocalyptic number.

2011313400000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2011313400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3500848431360).

2011313400000 is an abundant number, since it is smaller than the sum of its proper divisors (4990383462720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2011313400000 is an equidigital number, since it uses as much as digits as its factorization.

2011313400000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 176490 (or 176460 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 2011313400000 its reverse (43131102), we get a palindrome (2011356531102).

The spelling of 2011313400000 in words is "two trillion, eleven billion, three hundred thirteen million, four hundred thousand".