Base | Representation |
---|---|
bin | 11101010001001101010… |
… | …010101101001110011111 |
3 | 21010021121211202220022112 |
4 | 131101031102231032133 |
5 | 230423211402201444 |
6 | 4135555243304235 |
7 | 265212626121326 |
oct | 35211522551637 |
9 | 7107554686275 |
10 | 2011341443999 |
11 | 70600689a5a8 |
12 | 28598a21b07b |
13 | 11789013a694 |
14 | 6d4c6c410bd |
15 | 374bda1569e |
hex | 1d44d4ad39f |
2011341443999 has 2 divisors, whose sum is σ = 2011341444000. Its totient is φ = 2011341443998.
The previous prime is 2011341443983. The next prime is 2011341444029. The reversal of 2011341443999 is 9993441431102.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2011341443999 - 24 = 2011341443983 is a prime.
It is a super-2 number, since 2×20113414439992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2011341443959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1005670721999 + 1005670722000.
It is an arithmetic number, because the mean of its divisors is an integer number (1005670722000).
Almost surely, 22011341443999 is an apocalyptic number.
2011341443999 is a deficient number, since it is larger than the sum of its proper divisors (1).
2011341443999 is an equidigital number, since it uses as much as digits as its factorization.
2011341443999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 839808, while the sum is 50.
The spelling of 2011341443999 in words is "two trillion, eleven billion, three hundred forty-one million, four hundred forty-three thousand, nine hundred ninety-nine".
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