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20114031401 = 41771481531
BaseRepresentation
bin10010101110111000…
…111100001100101001
31220220210002122220222
4102232320330030221
5312143143001101
613123521255425
71311305305652
oct225670741451
956823078828
1020114031401
118591934552
123a94194575
131b871c1c39
14d8b4ca529
157cac9301b
hex4aee3c329

20114031401 has 4 divisors (see below), whose sum is σ = 20114554704. Its totient is φ = 20113508100.

The previous prime is 20114031397. The next prime is 20114031403. The reversal of 20114031401 is 10413041102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 20114031401 - 22 = 20114031397 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 20114031401.

It is not an unprimeable number, because it can be changed into a prime (20114031403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198995 + ... + 282536.

It is an arithmetic number, because the mean of its divisors is an integer number (5028638676).

Almost surely, 220114031401 is an apocalyptic number.

It is an amenable number.

20114031401 is a deficient number, since it is larger than the sum of its proper divisors (523303).

20114031401 is an equidigital number, since it uses as much as digits as its factorization.

20114031401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 523302.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 20114031401 its reverse (10413041102), we get a palindrome (30527072503).

The spelling of 20114031401 in words is "twenty billion, one hundred fourteen million, thirty-one thousand, four hundred one".

Divisors: 1 41771 481531 20114031401