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201143402143 = 5314207267133
BaseRepresentation
bin1011101101010100010…
…1001011111010011111
3201020012000210112100221
42323111011023322133
511243420202332033
6232223133102211
720350343464645
oct2732505137237
9636160715327
10201143402143
1178339230152
1232b96627967
1315c771880a8
149a41cbb195
155373a3012d
hex2ed514be9f

201143402143 has 8 divisors (see below), whose sum is σ = 204953753088. Its totient is φ = 197333613984.

The previous prime is 201143402123. The next prime is 201143402149. The reversal of 201143402143 is 341204341102.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 201143402143 - 25 = 201143402111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (201143402149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 619405 + ... + 886537.

It is an arithmetic number, because the mean of its divisors is an integer number (25619219136).

Almost surely, 2201143402143 is an apocalyptic number.

201143402143 is a deficient number, since it is larger than the sum of its proper divisors (3810350945).

201143402143 is a wasteful number, since it uses less digits than its factorization.

201143402143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 281393.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 201143402143 its reverse (341204341102), we get a palindrome (542347743245).

The spelling of 201143402143 in words is "two hundred one billion, one hundred forty-three million, four hundred two thousand, one hundred forty-three".

Divisors: 1 53 14207 267133 752971 14158049 3795158531 201143402143