Base | Representation |
---|---|
bin | 11101010001011000100… |
… | …111011000111001100111 |
3 | 21010022010002020102201211 |
4 | 131101120213120321213 |
5 | 230424104020241033 |
6 | 4140030151132251 |
7 | 265220423626135 |
oct | 35213047307147 |
9 | 7108102212654 |
10 | 2011531415143 |
11 | 7060a4052748 |
12 | 285a21974087 |
13 | 1178c05c2c43 |
14 | 6d504172755 |
15 | 374d053d2cd |
hex | 1d4589d8e67 |
2011531415143 has 4 divisors (see below), whose sum is σ = 2012076401608. Its totient is φ = 2010986428680.
The previous prime is 2011531415123. The next prime is 2011531415167. The reversal of 2011531415143 is 3415141351102.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2011531415143 - 229 = 2010994544231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2011531415123) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 272487696 + ... + 272495077.
It is an arithmetic number, because the mean of its divisors is an integer number (503019100402).
Almost surely, 22011531415143 is an apocalyptic number.
2011531415143 is a deficient number, since it is larger than the sum of its proper divisors (544986465).
2011531415143 is an equidigital number, since it uses as much as digits as its factorization.
2011531415143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 544986464.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 2011531415143 its reverse (3415141351102), we get a palindrome (5426672766245).
The spelling of 2011531415143 in words is "two trillion, eleven billion, five hundred thirty-one million, four hundred fifteen thousand, one hundred forty-three".
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