Base | Representation |
---|---|
bin | 1001001001011110010011… |
… | …00010111011010000001111 |
3 | 2122020010202022222112222111 |
4 | 10210233021202323100033 |
5 | 10114043012041120213 |
6 | 110441253535324451 |
7 | 4144245623034403 |
oct | 444571142732017 |
9 | 78203668875874 |
10 | 20116713223183 |
11 | 64564a519a085 |
12 | 230a906680727 |
13 | b2bcc8568745 |
14 | 4d7922c6b103 |
15 | 24d4364eba3d |
hex | 124bc98bb40f |
20116713223183 has 2 divisors, whose sum is σ = 20116713223184. Its totient is φ = 20116713223182.
The previous prime is 20116713223169. The next prime is 20116713223273. The reversal of 20116713223183 is 38132231761102.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 20116713223183 - 213 = 20116713214991 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (20116713223583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10058356611591 + 10058356611592.
It is an arithmetic number, because the mean of its divisors is an integer number (10058356611592).
Almost surely, 220116713223183 is an apocalyptic number.
20116713223183 is a deficient number, since it is larger than the sum of its proper divisors (1).
20116713223183 is an equidigital number, since it uses as much as digits as its factorization.
20116713223183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72576, while the sum is 40.
Adding to 20116713223183 its reverse (38132231761102), we get a palindrome (58248944984285).
The spelling of 20116713223183 in words is "twenty trillion, one hundred sixteen billion, seven hundred thirteen million, two hundred twenty-three thousand, one hundred eighty-three".
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